/*

Description:

Your grandfather criticises your overuse of the word ‘like’, claiming that it makes up more than 5% of the total words you speak.

You argue that it is much lower than this and so to settle the debate, you have been fitted with a recorder that stores every word you say as a string in an array.

Your task is to make an algorithm that returns true if ‘like’ accounts for more than 5% of words in the array, otherwise false (if no words are spoken, return false also).

evalLikes([‘I’,’am’,’sooo’,’like’,’tired’]) // ==> true;

evalLikes([‘THIS’,’IS’,’LIKE’,’TERRIBLE’]) // ==> true;

evalLikes([‘likely’,’story’]) // ==> false;

Your solution must be case-insensitive but you do not need to worry about punctuation (the device you have been fitted with automatically filters this out).

*/

var evalLikes = function(words){

let likes=words.join(‘ ‘).match(/blikeb/gi)

return likes?likes.length/words.length>=0.05:false

}